题解 | 数字颠倒
数字颠倒
https://www.nowcoder.com/practice/ae809795fca34687a48b172186e3dafe
import sys
p = sys.stdin.readline().strip()
'''
st = str(p)
re = ''.join(reversed(p))
print(re)
'''
st_n = str(p)
lent = len(st_n)
re_num = 0
num = int(p)
while num > 0:
last_n = num % 10
re_num = re_num * 10 + last_n
num = num//10
st_re_n = str(re_num)
lent_re = len(st_re_n)
s = 0
if lent_re < lent:
s = lent-lent_re
print('0' * s + st_re_n)
想着第一种有点简单粗暴，还是用数学方法又练一次
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