题解 | 矩阵转置
矩阵转置
https://www.nowcoder.com/practice/351b3d03e410496ab5a407b7ca3fd841
#include <stdio.h>
int main()
{
int n = 1;//行数
int m = 1;//列数
while (scanf("%d %d", &n, &m) == 2 && n <= 10 && m <= 10)
{
int arr[n][m];
int i = 0;
int j = 0;
for (i = 0; i < n; i++) //第一行 第二行
{
for (j = 0; j < m; j++)// 1 2 3 4 5 6
{
scanf("%d", &arr[i][j]);
}
}
int arr2[m][n];
for (j = 0; j < m; j++)
{
for (i = 0; i < n; i++)
{
arr2[j][i] = arr[i][j];
printf("%d ",arr2[j][i]);
}
printf("\n");
}
}
return 0;
}
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