题解 | 宝石计数
宝石计数
https://www.nowcoder.com/practice/d7c20bd9aa094e35b465b566eec86cf2
#
# 代码中的类名、方法名、参数名已经指定，请勿修改，直接返回方法规定的值即可
#
#
# @param jewels string字符串
# @param stones string字符串
# @return int整型
#
import bisect
class Solution:
def numJewelsInStones(self , jewels: str, stones: str) -> int:
# write code here
S =set()#存储j中所有不同的字符
result = 0
for char in jewels:
S.add(char)
for char in stones:
if char in S:#若set中有s的字符 结果+1
result+=1
return result
查看3道真题和解析