从基础到进阶:gh_mirrors/leet 项目助力字符串重排题解(308)

# 🔍 从基础到进阶:gh_mirrors/leet 项目助力字符串重排题解 🚀

字符串重排是算法面试中的常见题型,也是检验程序员基本功的试金石。今天我们就来探索如何利用开源项目 **gh_mirrors/leet** 从基础到进阶掌握这类题目!💡

## 🔧 基础篇:理解字符串重排
字符串重排问题的核心是判断两个字符串是否互为排列组合(Anagram)。最基础的方法是:
1️⃣ 排序比较法:将字符串排序后比较
2️⃣ 哈希计数法:统计每个字符出现的频率

```python
# 排序法示例
def is_anagram(s: str, t: str) -> bool:
  return sorted(s) == sorted(t)
```

## 🛠️ 进阶篇:gh_mirrors/leet 实战
gh_mirrors/leet 项目提供了大量字符串重排的变种题目和优化解法。比如:

🌟 **变位词分组**:给定字符串数组,将变位词分组
```python
from collections import defaultdict

def group_anagrams(strs):
  ans = defaultdict(list)
  for s in strs:
    key = "".join(sorted(s))
    ans[key].append(s)
  return list(ans.values())
```

🌟 **最小窗口子串**:在字符串S中找到包含T所有字符的最短子串
```python
# 滑动窗口解法
def min_window(s: str, t: str) -> str:
  # 实现略...
```

## 🎯 项目优势
gh_mirrors/leet 的优势在于:
- 📚 分类清晰的题目集合
- ⚡ 多种解法对比
- 🧠 复杂度分析
- 🏆 真实面试题收录

## 💪 练习建议
1. 先掌握基础解法
2. 通过项目学习优化技巧
3. 尝试解决变种问题
4. 参与项目讨论和贡献

字符串重排看似简单,但蕴含着丰富的算法思想。借助 gh_mirrors/leet 项目,你一定能攻克这类题型!🎉 现在就去 GitHub 探索吧!🔗
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