题解 | 特殊的科学计数法

#include <stdio.h>
#include <string.h>

int main(void) {
    char N[1000005];
    scanf("%s", N);
    
    int len = strlen(N);
    
    int a = N[0] - '0';
    int b = N[1] - '0';
    int c = len - 1;
    
    if (len == 2) {
        printf("%d.%d*10^%d\n", a, b, c);
    } 
    else {
        if (N[2] >= '5') {
            b++;
            if (b == 10) {
                b = 0;
                a++;
                if (a == 10) {
                    a = 1;
                    c++;
                }
            }
        }
        printf("%d.%d*10^%d\n", a, b, c);
    }
    return 0;
}