题解 | 反转链表

/*
 * function ListNode(x){
 *   this.val = x;
 *   this.next = null;
 * }
 */
/**
 * 代码中的类名、方法名、参数名已经指定，请勿修改，直接返回方法规定的值即可
 *
 * 
 * @param head ListNode类 
 * @return ListNode类
 */
function ReverseList( head ) {
    if (!head || (!head.val && head.val !== 0)) {
        return null;
    }
    let cur = head, pre = null;
    while (cur && (!!cur.val || cur.val === 0)) {    
        const next = cur.next;
        cur.next = pre;
        pre = cur;
        cur = next;
    }
    return pre;
}
module.exports = {
    ReverseList : ReverseList
};

好像这里对0不处理，也能正常通过。