题解 | 牛牛的矩阵相加
牛牛的矩阵相加
https://www.nowcoder.com/practice/730b90507602412fac90a3f106bfa0cd
list1 = [[1,2,3],[4,5,6],[7,8,9]] n = int (input()) for i in list1: for j in range(len(i)): i[j] *= n print(list1)
漂亮
牛牛的矩阵相加
https://www.nowcoder.com/practice/730b90507602412fac90a3f106bfa0cd
list1 = [[1,2,3],[4,5,6],[7,8,9]] n = int (input()) for i in list1: for j in range(len(i)): i[j] *= n print(list1)
漂亮
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