题解 | 牛牛的矩阵相加
牛牛的矩阵相加
https://www.nowcoder.com/practice/730b90507602412fac90a3f106bfa0cd
a =[[1,2,3],[4,5,6],[7,8,9]] n = int(input()) b = [[j*n for j in i] for i in a]#嵌套列表推导式 print(b)
牛牛的矩阵相加
https://www.nowcoder.com/practice/730b90507602412fac90a3f106bfa0cd
a =[[1,2,3],[4,5,6],[7,8,9]] n = int(input()) b = [[j*n for j in i] for i in a]#嵌套列表推导式 print(b)
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