题解 | 查询成绩
查询成绩
https://www.nowcoder.com/practice/ef30689ae065434c89c129e9dfe1b4cd
# with t1 as(
# select
# a.sId,
# b.cId,
# c.cname,
# b.score
# from Student as a
# left join SC as b on a.sId=b.sId
# left join Course c on b.cId=c.cId
# )
# select
# count(*)
# from(
# select
# t1.sId,
# avg(t1.score) as avg_score
# from t1
# group by t1.sId
# having avg_score > 60
# ) t2
select
count(*)
from(
select
sId
from SC
group by sId
having avg(score) >60
) a
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