题解 | 从单向链表中删除指定值的节点
从单向链表中删除指定值的节点
https://www.nowcoder.com/practice/f96cd47e812842269058d483a11ced4f
s = list(map(int, input().split()))
n = s[0]
h=s[1]
k = s[2*n]
# print(n)
# print(k)
l_1 = s[1:2*n+1]
# print(l_1)
l_2 = [h]
n1 = 2*n-1
i1=0
for a in range(1,n1,2):
# print(a)
l_2.insert(l_2.index(l_1[a+1])+1,l_1[a])
# print(l_2)
# print(i1)
# print(i1)
# del l_2[i1]
for i in range(len(l_2)):
if l_2[i] ==k:
continue
print(l_2[i],end=" ")
