题解 | 矩阵转置

矩阵转置

https://www.nowcoder.com/practice/351b3d03e410496ab5a407b7ca3fd841

import sys

n, m = map(int, input().split())
arr = list(input().split() for _ in range(n))
newarr = [["0"] *n for _ in range(m)]

for i in range(n):
    for j in range(m):
        newarr[j][i] = arr[i][j]
for i in newarr:
    print(' '.join(i))
    # print(*i)

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