题解 | 跳台阶

#
# 代码中的类名、方法名、参数名已经指定，请勿修改，直接返回方法规定的值即可
#
# 
# @param number int整型 
# @return int整型
#
class Solution:
    def jumpFloor(self , number: int) -> int:
        # write code here
        if number == 1:
            return 1
        if number == 2:
            return 2
        a = 1
        b = 1
        res = 0
        for i in range(2,number+1):
            res = a+b
            a = b
            b = res
        return res