题解 | 删除链表的节点

# class ListNode:
#     def __init__(self, x):
#         self.val = x
#         self.next = None
#
# 代码中的类名、方法名、参数名已经指定，请勿修改，直接返回方法规定的值即可
#
# 
# @param head ListNode类 
# @param val int整型 
# @return ListNode类
#
class Solution:
    def deleteNode(self , head: ListNode, val: int) -> ListNode:
        # write code here
        if head == None:
            return head
        
        pre = head
        cur = head.next

        if pre.val == val:
            return cur

        while cur:
            if cur.val == val:
                pre.next = cur.next
                return head
            pre = cur
            cur = cur.next