（1）对于前置递增和后置递增可以通过递增运算符重构来实现

可以实现一下例子

using namespace std;
int main()
{
	int a=10;
	cout<<a++<<endl;
	cout<<a<<endl;
	int b=10;
	cout<<++b<<endl;
	cout<<b<<endl;
}

【1】实现前置递增：

using namespace std;
class myteger{
	friend ostream& operator<<(ostream& cout,myteger p);
	public:
		myteger(){
			m_Num=0;
		}
		myteger& operator++(){
			m_Num++;
			return *this;
		}//记住返回引用，不是返回值
	private:
		int m_Num;
};
ostream& operator<<(ostream& cout,myteger p){
	cout<<p.m_Num;
	return cout;
}

void test01(){
	myteger myint;
	cout<<myint<<endl;
	cout<<++myint<<endl;
	cout<<myint<<endl;
}

int main()
{
	test01();
}

【2】实现后置递增

和前置引用略有不同，记住后置引用返回的是值

using namespace std;
class myteger{
	friend ostream& operator<<(ostream& cout,myteger p);
	public:
		myteger(){
			m_Num=0;
		}
		myteger& operator++(){
			m_Num++;
			return *this;
		}
		myteger operator++(int)//占位参数，用于区别前置的符号重构函数 
		{
			myteger temp=*this;
			m_Num++;
			return temp; 
		}
	private:
		int m_Num;
};
ostream& operator<<(ostream& cout,myteger p){
	cout<<p.m_Num;
	return cout;
}

void test01(){
	myteger myint;
	cout<<myint<<endl;
	cout<<++myint<<endl;
	cout<<myint<<endl;//前置引用例子 
	cout<<myint++<<endl;
	cout<<myint<<endl;//后置引用例子 
}

int main()
{
	test01();
}