题解 | 计算一元二次方程

#include <stdio.h>
#include <math.h>

int main() { 
    float a,b,c,m,x1,x2;
    
    
    while((scanf("%f %f %f\n",&a,&b,&c) != EOF)){
        m = b * b - 4 * a * c;
        float n = sqrt (m);
        float p = sqrt (-m);

        if(a == 0){
            printf("Not quadratic equation");
        }else if(a != 0){
           if(m == 0){
            float j1 = (-b + n) / (2 * a);
            if(j1 == 0){
                printf("x1=x2=0.00\n");
            }else{
            printf("x1=x2=%.2f\n",j1);
            }
           }else if(m > 0){
            printf("x1=%.2f;x2=%.2f\n",(-b - n) / (2 *a),(-b + n) / (2 * a));
           }else if(m < 0){
            printf("x1=%.2f-%.2fi;x2=%.2f+%.2fi\n",(-b) / (2 * a),p / (2 * a),(-b) / (2 * a),p / (2 *a));
           }
        }
    }
    return 0;//虽然运行得了，但我总感觉有点问题，但具体又说不出来是哪？
}