题解 | 输入n个整数，输出其中最小的k个
输入n个整数，输出其中最小的k个
https://www.nowcoder.com/practice/69ef2267aafd4d52b250a272fd27052c
const rl = require("readline").createInterface({ input: process.stdin });
var iter = rl[Symbol.asyncIterator]();
const readline = async () => (await iter.next()).value;
void async function () {
// Write your code here
let a = await readline()
let line = a.split(' ')
let b = await readline();
let array = b.split(' ').map(a => parseInt(a)).sort((a,b)=>a-b);
let num = parseInt(line[1])
//console.log(num)
let ans = ""
for(let i=0;i<num;i++){
ans +=array[i] +" "
}
console.log(ans.trim())
}()
写得乱七八糟的，顺便要记得readline返回的是一个Promise，解析后才是字符串，因为Promise没有split()方法所以不能直接对await readline()后面接上split()等Promise没有的方法
