题解 | 日期累加

#include<iostream>
#include<algorithm>
#include<string>
using namespace std;
void nextday(int& y, int& m, int& d) {
	int dayMonth[] = { 0,31,28,31,30,31,30,31,31,30,31,30,31 }; 
	bool isLeap = y % 400 == 0 || y % 4 == 0 && y % 100 != 0;
	if (isLeap) {
		dayMonth[2] = 29;
	}
	else {
		dayMonth[2] = 28;
	}
	d++;
	if (d > dayMonth[m]) {
		m++;
		d = 1;
	}
	if (m > 12) {
		m = 1;
		y++;
	}
}
int main() {
	int n;
	int year, month, day, t;
	cin >> n;
	for (int i = 0; i < n; i++) {
		cin >> year >> month >>day >> t;
		while (t != 0) {
			t--;
			nextday(year, month, day);
		}
		printf("%04d-%02d-%02d\n", year, month, day);//格式化控制输出,别忘了最后要输出换行
	}
	return 0;
}