题解 | 输出单向链表中倒数第k个结点
输出单向链表中倒数第k个结点
https://www.nowcoder.com/practice/54404a78aec1435a81150f15f899417d
while True:
try:
n = int(input())
data = [int(i) for i in input().split()]
k = int(input())
print(data[-k])
except:
break
得走出这种状态，不能一直困在那里面，哪不行就去提升哪，你一动不动那指定改变不了未来，动起来，积少成多才能越来越好