题解 | 顾客登录名
select
cust_id,
cust_name,
upper(concat (left (cust_name, 2), left (cust_city, 3))) user_login
from
test.Customers
select
cust_id,
cust_name,
upper(concat (left (cust_name, 2), left (cust_city, 3))) user_login
from
test.Customers
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