题解 | 删除字符串中出现次数最少的字符

string = input('')
dic = {}
# 创建字母-次数字典
for i in range(len(string)):
    s = string[i]
    if s in dic:
        dic[s] += 1
    else:
        dic[s] = 1
# 出现最小次数及字母
min_value = min(dic.values())
min_str = []
for i in dic:
    if dic[i] == min_value:
        min_str.append(i)
# 新字符串
newstr = ''
for i in range(len(string)):
    A = string[i]
    if A in min_str:
        continue
    else:
        newstr = newstr + A
# 输出
print(newstr)