题解 | #求最小公倍数#

'''
  2   12 14
       6  7    2*6*7=84

  4   12 16
       3  4    4*3*4=48
  2   12 16 
  2    6  8
       3  4
'''
'''
# 遍历：数字越大，越耗时，超时
num=input().split()
a=int(num[0])
b=int(num[1])
for i in range(1,a*b+1):
    if i%a==0 and i%b==0:
        print(i)
        break
'''
# 按照数学求最小公倍数的过程求解，运行时间较短
num=list(map(int,input().split()))
a=num[0]
b=num[1]
#print(num,a,b)
comul=1
for i in range(2,min(num)+1):
    while a%i==0 and b%i==0:
        comul *= i
        a=a/i
        b=b/i
comul=int(comul*a*b)
print(comul)