题解 | #公共子串计算#

s1 = input().lower()
s2 = input().lower()

p = 0
if len(s1) > len(s2):
    s1, s2 = s2, s1

for i in range(len(s1)):
    for j in range(i, len(s1)):
        if s1[i : j + 1] in s2 and j + 1 - i > p:
            p = j + 1 - i
print(p)