题解 | #质数因子#
质数因子
https://www.nowcoder.com/practice/196534628ca6490ebce2e336b47b3607
n = int(input())
for i in range(2, int(n ** 0.5) + 1):
if n % i == 0:
while n % i == 0:
print(i, end=" ")
n = n // i
if n != 1: # 如果最后n不等于1，说明n本身是一个质因子
print(n)
