题解 | #xxx定律#写个while循环就行

//Java版代码
import java.util.Scanner;
public class Main {
    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        while (sc.hasNextInt()) {
            int n = sc.nextInt();
            int count = 0;
            while (n != 1) {
                if (n % 2 == 0) {
                    n = n / 2;
                } else {
                    n = (3 * n + 1) / 2;
                }
                count++;
            }
            System.out.println(count);
        }
    }
}
#Python版代码
while True:
    try:
        n = int(input())
        count = 0
        while n != 1:
            if n % 2 == 0:
                n //= 2
            else:
                n = (3 * n + 1) // 2
            count += 1
        print(count)
    except:
        break