python参考

def min_operations_to_alternate(s):

n = len(s)

cnt0 = s.count('0')

cnt1 = s.count('1')

sum1 = 0

j = 0

for i in range(n):

if s[i] == '0':

sum1 += abs(i - j)

j += 2

sum2 = 0

j = 0

for i in range(n):

if s[i] == '1':

sum2 += abs(i - j)

j += 2

if cnt0 == cnt1 + 1:

return sum1

elif cnt1 == cnt0 + 1:

return sum2

else:

return min(sum1, sum2)

# 输入

s = input().strip()

# 输出结果

result = min_operations_to_alternate(s)

print(result)