B题是否无法用Python通过？

同样的思路用Python会报错，报错内容为：“程序异常退出，请检查是否存在语法错误或者数组越界非法访问等情况

Warning: cannot find your CPU L2 cache size in /proc/cpuinfo

Traceback (most recent call last):

File "a.pypy3", line 8, in <module>

nums.append(int(input()))

ValueError: invalid literal for int() with base 10: '0 1073741823'

”

但C++却可以正常通过。

代码如下：

Python:

from collections import defaultdict

if __name__ == '__main__':
    n, m = map(int, input().split())

    nums = []
    for i in range(n):
        nums.append(int(input()))

    ans = 0
    for i in range(m - 1, -1, -1):
        mask_to_nums = defaultdict(lambda: defaultdict(int))
        ok = False
        for j in range(n):
            cur = nums[j] & ans
            mask_to_nums[cur][nums[j] >> i & 1] += 1
            if mask_to_nums[cur][nums[j] >> i & 1] >= 2:
                ok = True
                break

        if ok:
            ans |= 1 << i

    print(ans)

C++:

#define _CRT_SECURE_NO_WARNINGS
#include <iostream>
#include <vector>
#include <array>
#include <algorithm>
#include <bitset>
#include <string>
#include <sstream>
#include <chrono>
#include <cstring>
#include <climits>
#include <cassert>
#include <cmath>
#include <stack>
#include <queue>
#include <numeric>
#include <set>
#include <map>
#include <unordered_set>
#include <unordered_map>
#include <iomanip>
#include <tuple>
#include <functional>
using namespace std;

typedef long long LL;
typedef unsigned long long ULL;

constexpr int INF = 0x3f3f3f3f;
constexpr int MOD = 998244353;

int main() {
    std::ios::sync_with_stdio(false);
    std::cin.tie(nullptr);

    int n, m;
    cin >> n >> m;

    vector<int> nums(n);
    for (int i = 0; i < n; ++i) {
        cin >> nums[i];
    }

    int ans = 0;
    for (int i = m - 1; i >= 0; --i) {
        unordered_map<int, unordered_map<int, int>> mask_to_nums;
        bool ok = false;
        for (int j = 0; j < n; ++j) {
            int cur = nums[j] & ans;
            mask_to_nums[cur][(nums[j] >> i) & 1]++;
            if (mask_to_nums[cur][(nums[j] >> i) & 1] >= 2) {
                ok = true;
                break;
            }
        }

        if (ok) {
            ans |= 1 << i;
        }
    }

    cout << ans << endl;
    return 0;
}