题解 | #牛牛的矩阵相加#
牛牛的矩阵相加
https://www.nowcoder.com/practice/730b90507602412fac90a3f106bfa0cd
n = int(input())
matrix = [
[1,2,3],
[4,5,6],
[7,8,9]
]
result_matrix = [[0 for _ in range(len(matrix[0]))] for _ in range(len(matrix))]
for i in range(len(matrix)):
for j in range(len(matrix[0])):
result_matrix[i][j] = matrix[i][j] * n
print(result_matrix)
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