题解 | #删除有序链表中重复的元素-I#
删除有序链表中重复的元素-I
https://www.nowcoder.com/practice/c087914fae584da886a0091e877f2c79
# class ListNode:
# def __init__(self, x):
# self.val = x
# self.next = None
#
# 代码中的类名、方法名、参数名已经指定，请勿修改，直接返回方法规定的值即可
#
#
# @param head ListNode类
# @return ListNode类
#
class Solution:
def deleteDuplicates(self , head: ListNode) -> ListNode:
# write code here
if head is None or head.next is None:
return head
s = set()
while head:
s.add(head.val)
head = head.next
num_s = list(s)
num_s.sort()
new_head = ListNode(-1)
cur = new_head
for i in num_s:
cur.next = ListNode(i)
cur = cur.next
return new_head.next
使用集合筛掉重复元素，转化为列表，排序，再转换为链表，输出
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