题解 | #牛牛的Ackmann#
牛牛的Ackmann
https://www.nowcoder.com/practice/3a7a4c26420c4358a1a5cda3da2fa1c8
#include <stdio.h>
int Ackmann(int m,int n)
{
if(m > 0&& n > 0)
{
return Ackmann(m-1, Ackmann(m, n-1));
}else if(m > 0 && n == 0)
{
return Ackmann(m-1, 1);
}
return n+1;
}
int main() {
int a,b;
scanf("%d %d",&a,&b);
int ret = Ackmann(b,a);
printf("%d",ret);
return 0;
}
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