题解 | #二分查找-I#
二分查找-I
https://www.nowcoder.com/practice/d3df40bd23594118b57554129cadf47b
/**
* 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可
*
*
* @param nums int整型一维数组
* @param numsLen int nums数组长度
* @param target int整型
* @return int整型
*/
int search(int* nums, int numsLen, int target ) {
// write code here
int start = 0;
int end = numsLen - 1;
int mid;
if(nums[start] == target){
return start;
}
if(nums[end] == target) {
return end;
}
while (start + 1 < end){
mid = start + (end - start) / 2;
printf("mid = %d, start = %d, end = %d\n", mid, start, end);
printf("nums[%d] = %d \n", mid, nums[mid]);
if(target == nums[mid]){
printf("target == nums[mid]\n");
return mid;
}else if(target > nums[mid]){
printf("target > nums[mid]\n");
start = mid;
}else {
printf("target < nums[mid]\n");
end = mid;
}
}
return -1;
}
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