题解 | #求最大连续bit数#

import java.util.Scanner;

// 注意类名必须为 Main, 不要有任何 package xxx 信息
public class Main {

    private static int maxCount = 0;

    public static void main(String[] args) {
        Scanner in = new Scanner(System.in);
        int a = 0;
        // 注意 hasNext 和 hasNextLine 的区别
        while (in.hasNextInt()) { // 注意 while 处理多个 case
            a = in.nextInt();
        }

        String s = Integer.toBinaryString(a);
        max(s);
        System.out.print(maxCount);
    }

    private static void max(String s){
        
        int len = s.length();
        int tempCount =0;
        for(int i = 0; i < len;i++){
            char c = s.charAt(i);
            if(c == '1'){
                tempCount += 1;
                if(i + 1 < len){
                    if(s.charAt(i+1) == '0'){
                        if(tempCount > maxCount){
                            maxCount = tempCount;
                            tempCount = 0;
                        } else{
                            tempCount = 0;
                        }
                    }
                } else{
                    if(tempCount > maxCount){
                        maxCount = tempCount;
                    }
                }
            }
        }
    }
}