题解 | #统计成绩#
统计成绩
https://www.nowcoder.com/practice/cad8d946adf64ab3b17a555d68dc0bba
#include <stdio.h> int main() { double n; scanf("%lf", &n); double maxx = 0, minn = 1e9, average = 0, sum = 0; //根据题目给的范围给定一个较大的min值 for (int i = 0; i < n; ++i) { double x; scanf("%lf", &x); //每输入一次就进行一次判断和加和 if (x > maxx)maxx = x; if (x < minn)minn = x; sum += x; } average = sum / n; printf("%.2f %.2f %.2f", maxx, minn, average); return 0; }