题解 | #二维数组操作#

#include <stdio.h>

int main() {
    int m, n;
    int x1, x2, y1, y2;
    int x, y;
    int x3, y3;

    while (scanf("%d %d\n", &m, &n) != EOF) {
        int arr[m - 1][n - 1];


        scanf("%d %d %d %d\n", &x1, &y1, &x2, &y2);


        scanf("%d\n", &x);
        scanf("%d\n", &y);


        scanf("%d %d", &x3, &y3);

        if (m >= 0 && m <= 9 && n >= 0 && n <= 9) {
            printf("0\n");
        } else {
            printf("-1\n");
        }

        if (x1 >= 0 && x1 < m && x2 >= 0 && x2 < m && y1 >= 0 && y1 < n && y2 >= 0 &&
                y2 < n) {
            printf("0\n");
            /*  int temp = arr[x1][y1];
              arr[x1][y1] = arr[x2][y2];
              arr[x2][y2] = temp;*/
        } else {
            printf("-1\n");
        }


        if (x >= 0 && x <= m - 1 && m  <= 8 && m > 0 ) {
            printf("0\n");
        } else {
            printf("-1\n");
        }
        if ( y >= 0 && y <= n - 1 && n  <= 8 && n > 0) {
            printf("0\n");
        } else {
            printf("-1\n");
        }

        /*输出未要求数组实际上改变

        if (m + 1 <= 9 && x < m) {
            printf("0\n");
            for (int i = m - 1; i >= x; i--) {
                for (int j = 0; j < n; j++) {
                    arr[i + 1][j] = arr[i][j];
                }

            }
        } else {
            printf("-1\n");
        }

        if (n + 1 <= 9 && y < n ) {
            printf("0\n");
            for (int i = n - 1; i >= y; i--) {
                for (int j = 0; j < m; j++) {
                    arr[j][i + 1] = arr[j][i];
                }

            }
        } else {
            printf("-1\n");
        }*/

        if (x3 >= 0 && x3 <= m - 1 && y3 >= 0 && y3 <= n - 1) {
            printf("0\n");
        } else {
            printf("-1\n");
        }
    }


    return 0;
}