题解 | #求最大连续bit数#

import sys

n = int(input())
n = bin(n)[2:]
num = []
one = False
two = True
count = 1
count_list = []
for i in n:
    num.append(i)
num = list(map(int,num))

for i in range(len(num)):
    if num[i] == 1:
        one = True
if one == False:
    print('0')

for i in range(len(num)-1):
    if num[i] == 1 and num[i+1] == 1:
        count +=1

if count == 1:
    print('1')
    two = False

count = 1

if one == True and two == True:
    for i in range(len(num)-1):
        if num[i] == 1 and num[i+1] == 1:
            count +=1
            count_list.append(count)
        else:
            count = 1
            count_list.append(count)

    print(max(count_list))