bite解法
环形链表的约瑟夫问题
https://www.nowcoder.com/practice/41c399fdb6004b31a6cbb047c641ed8a
/**
* 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可
*
*
* @param n int整型
* @param m int整型
* @return int整型
*/
typedef struct ListNode ListNode;
ListNode* BuyNode(int n)
{
ListNode* newnode = (ListNode*)malloc(sizeof(ListNode));
if (newnode == NULL)
{
exit(1);
}
newnode->val = n;
newnode->next = NULL;
return newnode;
}
ListNode* CreatCircle(int n)
{
ListNode* newHead, * newTail;
newHead = newTail = BuyNode(1);
for (int i = 2; i <= n; i++)
{
newTail->next = BuyNode(i);
newTail = newTail->next;
}
newTail->next = newHead;
return newTail;
}
int ysf(int n, int m) {
ListNode* prev, * pcur;
prev = CreatCircle(n);
pcur = prev->next;
int count = 1;
while (pcur->next != pcur)
{
if (count == m)
{
prev->next = pcur->next;
free(pcur);
pcur = prev->next;
count = 1;
}
else {
prev = pcur;
pcur = pcur->next;
count++;
}
}
return pcur->val;
}

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