Python题解 | #简单密码#

import sys

s = sys.stdin.readline().strip()
dict1 = {'a': '2', 'b': '2', 'c': '2', 'd': '3', 'e': '3', 'f': '3', 'g': '4', 'h': '4', 'i': '4', 'j': '5', 'k': '5', 'l': '5', 'm': '6', 'n': '6', 
         'o': '6', 'p': '7', 'q': '7', 'r': '7', 's': '7', 't': '8', 'u': '8', 'v': '8', 'w': '9', 'x': '9', 'y': '9', 'z': '9'}
res = ''
for i in s:
    if 'a' <= i <= 'z':
        res += dict1[i]
    elif 'A' <= i <= 'Y':
        res += chr(ord(i) + 33)
    elif i == 'Z':
        res += 'a'
    else:
        res += i

print(res)