题解 | #旋转链表#

旋转链表

https://www.nowcoder.com/practice/1ad00d19a5fa4b8dae65610af8bdb0ed

using System;
using System.Collections.Generic;

/*
public class ListNode
{
    public int val;
    public ListNode next;

    public ListNode (int x)
    {
        val = x;
    }
}
*/

class Solution {
    /**
     * 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可
     *
     *
     * @param head ListNode类
     * @param k int整型
     * @return ListNode类
     */
    public ListNode rotateLinkedList (ListNode head, int k) {
        // write code here
        // write code here
        if (head == null)
            return null;
        List<int> lsN = new List<int>();
        ListNode lnR = head;
        while (head != null) {
            lsN.Add(head.val);
            head = head.next;
        }
        int nLen = lsN.Count;
        k = k % nLen;
        if (k == 0)
            return lnR;
        List<int> lsNT = lsN.GetRange(lsN.Count - k, k);
        //lsNT.Reverse();//反序
        lsN.InsertRange(0, lsNT);
        head = lnR;
        for (int i = 0; i < nLen; i++) {
            head.val = lsN[i];
            head = head.next;
        }
        return lnR;
    }
}

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