题解 | #字符串加解密#
字符串加解密
https://www.nowcoder.com/practice/2aa32b378a024755a3f251e75cbf233a
#include <iostream>
#include<string>
using namespace std;
int main() {
string s1,s2;
while (cin >> s1 >> s2) { // 注意 while 处理多个 case
for(int i=0;i<s1.size();i++)//encoder
{
char tmp=s1[i];
if(s1[i]=='9')
{
s1[i]='0';
}
else if(s1[i]=='z')
{
s1[i]='A';
}
else if(s1[i]=='Z')
{
s1[i]='a';
}
else if((97<=s1[i])&&(122>s1[i]))
{
s1[i]=s1[i]-31;
}
else if((65<=s1[i])&&(90>s1[i]))
{
s1[i]=s1[i]+33;
}
else{
s1[i]=s1[i]+1;
}
}
cout<<s1<<endl;
for(int i=0;i<s2.size();i++)//decoder
{
char tmp=s2[i];
if(s2[i]=='0')
{
s2[i]='9';
}
else if(s2[i]=='A')
{
s2[i]='z';
}
else if(s2[i]=='a')
{
s2[i]='Z';
}
else if((97<s2[i])&&(122>=s2[i]))
{
s2[i]=s2[i]-33;
}
else if((65<s2[i])&&(90>=s2[i]))
{
s2[i]=s2[i]+31;
}
else{
s2[i]=s2[i]-1;
}
}
cout<<s2<<endl;
}
}
// 64 位输出请用 printf("%lld")
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