题解 | #链表内指定区间反转#
链表内指定区间反转
https://www.nowcoder.com/practice/b58434e200a648c589ca2063f1faf58c
# class ListNode:
# def __init__(self, x):
# self.val = x
# self.next = None
#
# 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可
#
#
# @param head ListNode类
# @param m int整型
# @param n int整型
# @return ListNode类
#
class Solution:
def reverseBetween(self , head: ListNode, m: int, n: int) -> ListNode:
# write code here
dummy = ListNode(-1)
dummy.next = head
p0 = dummy
for i in range(m-1):
p0 = p0.next
cur = p0.next
pre = None
for i in range(n-m+1):
nxt = cur.next
cur.next = pre
pre = cur
cur = nxt
p0.next.next = cur
p0.next = pre
return dummy.next
将链表内指定区间看作一个整体,对该区间翻转,随后连接头节点和尾节点。

