题解 | #牛牛的绩点#
牛牛的绩点
https://www.nowcoder.com/practice/de8bc3e736164786b07a4dd64ed172f7
n=0
s=0
a=[]
b=[]
l1=['A','B','C','D','F']
l2=[4.0,3.0,2.0,1.0,0.0]
l3=['1','2','3','4','5','6','7','8','9']
while True:
m=input()
if m in l1:
e=m
c=l1.index(e)
a.append(l2[c])
elif m in l3:
e=int(m)
b.append(e)
else:
break
for i in range(0,len(a)):
n=n+a[i]*b[i]
s=sum(b)
print('%.2f'%(n/s))
