题解 | #反转链表#

反转链表

https://www.nowcoder.com/practice/75e878df47f24fdc9dc3e400ec6058ca?tpId=295&tqId=23286&ru=/exam/oj&qru=/ta/format-top101/question-ranking&sourceUrl=%2Fexam%2Foj

/**
 * struct ListNode {
 *	int val;
 *	struct ListNode *next;
 * };
 */
/**
 * 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可
 *
 * 
 * @param head ListNode类 
 * @return ListNode类
 */
struct ListNode* ReverseList(struct ListNode* head ) {
    // write code here
    if((head == NULL) || (head->next == NULL))
        return head;
    struct ListNode* cur = head->next;
    struct ListNode* last = head;
    last->next = NULL;
    while(cur)
    {
        struct ListNode* p = cur->next;
        cur->next = last;
        last = cur;
        cur = p;
    }
    return last;
}

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