题解HJ86 | #求最大连续bit数#

import java.util.ArrayList;
import java.util.Comparator;
import java.util.List;
import java.util.Scanner;
import java.util.stream.Collectors;

// 注意类名必须为 Main, 不要有任何 package xxx 信息
public class Main {
    public static void main(String[] args) {
        Scanner in = new Scanner(System.in);

        Integer x = Integer.valueOf(in.nextLine());

        String binaryString = Integer.toBinaryString(x);


        int count = 0;

        List<Integer> resultList = new ArrayList<>();

        for (int i = 0; i < binaryString.length(); i++) {
            if ('1' == binaryString.charAt(i)) {
                count++;
                resultList.add(count);
            } else {
                count = 0;
            }
        }

        System.out.println(resultList.stream().sorted(
                               Comparator.reverseOrder()).collect(Collectors.toList()).get(0));
    }
}