题解 | #神仙打架#
神仙打架
https://ac.nowcoder.com/acm/problem/22235
通过cin输入流获取每个字符，将其转换为数字，注意要吸收回车
#include <bits/stdc++.h>
using namespace std;
int main()
{
int n, m, countnum = 0;
cin >> n >> m;
cin.get();
int haswin[n];
fill_n(&haswin[0], n, 0);
int count[n][m];
for (int i = 0; i < n; i++)
{
for (int j = 0; j < m; j++)
{
char a = cin.get();
count[i][j]=int(a-'0');
}
cin.get();
}
for (int j = 0; j < m; j++)
{
int maxnum = count[0][j];
for (int i = 1; i < n; i++)
{
if (count[i][j] > maxnum)
maxnum = count[i][j];
}
for (int i = 0; i < n; i++)
{
if (count[i][j] == maxnum)
haswin[i] = 1;
}
}
for (int i = 0; i < n; i++)
{
if (haswin[i] == 1)
countnum++;
}
cout << countnum;
}
投递华为等公司8个岗位 >
睿联技术公司福利 32人发布
，大厂实习随便冲，面经多少看点，hot100刷完，大厂随便挑了
