题解 | #奇偶统计#
奇偶统计
https://www.nowcoder.com/practice/04de8eb0ecab426fa6be3ae99af17210
#include <stdio.h>
int main()
{
int n=0,odd_numer=0,even_numer=0,i=0;
scanf("%d",&n);
for(i=1;i<=n;i++)
{
if(i%2==1)
odd_numer++;
else
even_numer++;
}
printf("%d %d\n",odd_numer,even_numer);
return 0;
}
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