题解 | #KiKi和酸奶#
KiKi和酸奶
https://www.nowcoder.com/practice/c7721f3a1b1a47a783974453e82cadbb
#include <stdio.h>
int main(void)
{
int n = 0,h = 0,m = 0,flag = 0;
scanf("%d%d%d",&n,&h,&m);
if(m <= n * h)
{
flag = m/h;
if(m%h == 0)
{
printf("%d",n - flag);
}
else
{
printf("%d",n - (flag+1));
}
}
return 0;
}