题解 | #挑7#
挑7
https://www.nowcoder.com/practice/ba241b85371c409ea01ac0aa1a8d957b
#include <bits/stdc++.h>
#include <regex>
using namespace std;
int main() {
int n;
cin >> n;
regex regex_pattern("\\d*[7]\\d*");
vector<int> res;
int count = 0;
for(int i = 7; i <= n; ++i){
if(i % 7 == 0){
count++;
res.push_back(i);
}else if(regex_match(to_string(i),regex_pattern)){
count++;
res.push_back(i);
}
}
// for(auto &i : res){
// cout << i << " ";
// }
cout << count << endl;
}
// 64 位输出请用 printf("%lld")

