题解|1、2、5分凑一元

#include <bits/stdc++.h>
using namespace std;

int main() {
	//i,j,k represent 1 cent, 2 cents and 5 cents respectively
	int res = 0;
	for(int i=0;i<=100;i++)
		for(int j =0;j<=50;j++)
			for(int k =0;k<=20;k++)
				if(i+2*j+5*k == 100)res++;
	cout<<res<<endl;
}

三重循环硬做的...递归了半天没做明白