题解|1、2、5分凑一元
#include <bits/stdc++.h> using namespace std; int main() { //i,j,k represent 1 cent, 2 cents and 5 cents respectively int res = 0; for(int i=0;i<=100;i++) for(int j =0;j<=50;j++) for(int k =0;k<=20;k++) if(i+2*j+5*k == 100)res++; cout<<res<<endl; }
三重循环硬做的...递归了半天没做明白