题解 | #尼科彻斯定理#

#include <iostream>
using namespace std;

int main() {
    int m;
    cin >> m;
    int a[m];
    int temp1 = (m * m * m) / m, temp2 = 1 - m;
    for (int i = 0; i < m; i++) {
        a[i] = temp1 + temp2;
        temp2 += 2;
    }
    for (int i = 0; i < m; i++) {
        cout << a[i];
        if (i != m - 1) {
            cout << "+";
        }
    }
    return 0;
}