题解 | #百鸡问题#

#include <iostream>
using namespace std;

void buy_chicken(int yuan){
    for(int x=0; x<=100; x++){
        for(int y=0; y<=100; y++){
            for(int z=0; z<=100; z++){
                if(x*5+y*3+z*(1.0/3.0)<=yuan && x+y+z==100){
                    cout<<"x="<<x<<",y="<<y<<",z="<<z<<endl;
                }
            }
        }
    }
}

int main() {
    int n;
    cin>>n;
    buy_chicken(n);
    return 0;
}